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#
What is the value of x in this equation?

\(\frac{\mathrm{(x+3)} }{\mathrm{4}} = \frac{\mathrm{(2x-3)} }{\mathrm{5}}\)

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Question:

\(\frac{\mathrm{(x+3)} }{\mathrm{4}} = \frac{\mathrm{(2x-3)} }{\mathrm{5}}\)

A
9

explanation

Always start with the given equation: \(\frac{\mathrm{(x+3)} }{\mathrm{4}} = \frac{\mathrm{(2x-3)} }{\mathrm{5}}\)

Cross-multiply denominators to eliminate each: 5(x+3)=4(2x−3)

Distribute each term through the parentheses: 5x+15=8x–12

Group similar terms by subtracting 5x from both sides, and adding 12 to both sides:

8x−5x=15+12

3x=27

Divide both sides by 3 to solve for x: \(x=27 \div 3=9\)

This answer can be verified by substituting it into the original equation.

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