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What is the value of b in the equation:

\(\frac{\mathrm{12} }{\mathrm{(4b-10)}} - \frac{\mathrm{8} }{\mathrm{(2b-6)}} = 0\)

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Question:

\(\frac{\mathrm{12} }{\mathrm{(4b-10)}} - \frac{\mathrm{8} }{\mathrm{(2b-6)}} = 0\)

A
1

explanation

\(\frac{\mathrm{12} }{\mathrm{(4b-10)}} - \frac{\mathrm{8} }{\mathrm{(2b-6)}} = 0\)

\(\frac{\mathrm{12} }{\mathrm{(4b-10)}} = \frac{\mathrm{8} }{\mathrm{(2b-6)}}\)

12(2b−6) = 8(4b−10)

24b−72 = 32b−80

−72+80 = 32b−24b

8 = 8b

b = 1

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