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Question:

In a competition, three teams, A, B and C, scored a total of 150 points.
If A scored 40% of this total and B scored four times as many points as C, what was the number of points scored by B?

A 72
explanation

Let a be the points earned by A, b be the points scored by B, and c be the points scored by C.
\(\frac{\mathrm{40} }{\mathrm{100}} = \frac{\mathrm{a} }{\mathrm{150}} \)
\(( \frac{\mathrm{40} }{\mathrm{100}}) \times 150 = a\)
a=60points
b = 4c
150=a+b+c
150=60+4c+c
150=60+5c
5c=150–60
\(c= \frac{\mathrm{90} }{\mathrm{5}}\)
c = 18 points
b=4c=\(4 \times 18 = 72 points\)

Comments

Bebe____

3 years ago

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CupcakeTurner

3 years ago

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Shelly84852

3 years ago

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